Scalar Multiplication 2

We can start doing more complicated things now.

Here's another matrix called B:

B = [ row 1: 7 , 1 row 2: -4 , 0 ]

Let's find

Just write it out with the matrices and start working:

3B - A = 3 [ row 1: 7 , 1 row 2: -4 , 0 ] - [ row 1: -4 , 0 row 2: 3 , 6 ]

= [ row 1: 21 , 3 row 2: -12 , 0 ] - [ row 1: -4 , 0 row 2: 3 , 6 ] = [ row 1: 25 , 3 row 2: -15 , -6 ]

YOUR TURN:

Here are some matrices:

A = [ row 1: -8 , 9 row 2: 1 , -3 ] B = [ row 1: 2 , -6 row 2: - 5, 10 ]

C = [ row 1: 0 , -4 row 2: 3 , 7 ]

Find .

1 2

of 2

Scalar Multiplication