Let's try another one like this.

Let's build the sequence whose nth term is given by

an = -3a sub( n - 1 ) + 5

and  a1 = 2

Here we go!

let n = 2:

a2 = -3a sub( 2 - 1) + 5 = -3a1 + 5 = -3 ( 2 ) + 5 = -1

let n = 3:

a3 = -3a2 + 5 = -3 ( -1 ) + 5 = 8

let n = 4:

a4 = -3a3 + 5 = -3 ( 8 ) + 5 = -19

let n = 5:

a5 = -3a4 + 5 = -3 ( -19 ) + 5 = 62

So, the sequence is

2 , -1 , 8 , -19 , 62 , ...

*When you build a sequence, finding the first five terms will usually do the job.


YOUR TURN:

Build the sequence (the first five terms) whose nth term is given by

an = 7a sub( n - 1 ) -2a sub( n - 2 )
 

a1 = 1 and a2 = 3