Let's do another one:

Graphf( x ) = ( 3x ) / ( x^2 + 2x - 8 )

2 things
and
2 sentences!

 

1The y-intercept:  Find f(0)
 

f( 0 ) = ( 3( 0 ) ) / ( ( 0 )^2 + 2( 0 ) - 8 ) = 0

( 0 , 0 ) nowhere else
 

2The x-interceptnumerator = 0, solve.

 

3x = 0  ...  x = 0

( 0 , 0 ) nowhere else

 
3Vertical asymptotesdenominator = 0, solve
 
x^2 + 2x - 8 = 0  ...  ( x - 2 )( x + 4 ) = 0  ...  x = 2  ,  x = -4The lines x = -4  and  x = 2

 

4Horizontal asymptote:
 
Look at3x / x^2

The line y = 0 ( the x-axis )

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* When this is the case, we're going to be forced to "quickie plot" a few points to nail the graph.  No, this isn't being a sissy -- we'll have no choice.  But, Calculus will fix this problem by telling us where the graphs are increasing and decreasing!